My requirement is to get each client's latest order, and then get top 100 records. Oracle Database has most likely copied the entire table into TEMP and written it out, just to get the first 10 rows. This query will get the first 10 records. The important point here is that it uses a subquery to do the ordering first, and then the outer query performs the rownum limiting. How to get a value from a single cell of a table by Oracle functions. Previous: Write a query to check if the first_name fields of the employees table contains numbers Next: Write a query to get monthly salary (round 2 decimal places) of all employees. Merge the temporary extents back to get the first 10 records when they are requested. Something like this can also indicate the first and last rows as you query... SQL> select empno, ename, hiredate 2 ,case row_number() over (order by hiredate) 3 when 1 then 'First Row' 4 when count(*) over then 'Last Row' 5 end as flag 6 from emp; EMPNO ENAME HIREDATE FLAG ----- ----- ----- ----- 7369 SMITH 17/12/1980 00:00:00 First Row 7499 ALLEN 20/02/1981 00:00:00 7521 WARD … When you use NO_WAIT, Oracle Forms displays a dialog to notify the operator if a record cannot be reserved for update immediately. Oracle has ROWNUM, so first query can be simplified – Bulat Sep 5 '14 at 11:42 1 @Bulat using row_number is more safe than using rownum, analytic function apply to the result set after the result set got ready, but oracle docs don't tell us when rownum is generated – neshkeev Sep 5 '14 at 12:19 Now, that is a lot of I/O. It returns the first value in an ordered set of values. Have another way to solve this solution? There are at least two different approaches which can be taken to return the first record in a group - in our working example the date when each page was first viewed and the IP address associated with that event. Internal query works fine. And in the main query I have a condition to only include rows where the rank is equal to 1, which will give me all of the employees who earn the smallest bonus in each department, and then I group by department id to get the count of rows for each department. I tried using OVER PARTITION BY clause, but somehow I'm not getting the desired result :select row_number() OVER(PARTITION BY leafv , value_group , l1d ,l2d ,l3d ,l4d ,l5d ,l6d ,l7d order by leafv , value_group , Clean up (release) the temporary extents as you are finished with them. But I don't know how to get first 100 based on the results. How to Write an Oracle Pagination Query This setting is useful for data densification. Different SQL syntax for Oracle 8i, 9i, 10g, 11g, and above. Answer: To retrieve the Top N records from a query, you can use the following syntax: SELECT * FROM (your ordered query) alias_name WHERE rownum <= Rows_to_return ORDER BY rownum; For example, if you wanted to retrieve the first 3 records from the suppliers table, sorted by supplier_name in ascending order, you would run the following query: Here is what we're going to explain. This is a variant of a top-1 query, as you may have noticed. SQL to return the first record in a group. If the first value in the set is null, then the function returns NULL unless you specify IGNORE NULLS. Without the NO_WAIT parameter, Oracle Forms keeps trying to obtain a lock without letting the operator cancel the process. You could change this query to suit your needs. Contribute your code (and comments) through Disqus. FIRST_VALUE is an analytic function. The first approach is to use an embedded select. The rownum is assigned after the ORDER BY because it’s in the outer query. 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